Question

50 joule of work is done in moving 3 coulomb of charge from one terminal of a battery to another terminal calculate the potential difference of​

Answer 1

Solution :

⏭ Given:

✏ Work done to moving a charge = 50J

✏ Magnitude of charge = 3C

⏭ To Find:

✏ Potential difference across the battery.

⏭ Formula:

✏ Formula of work done in terms of charge and potential difference is given by

$\star \: \underline{ \boxed{ \bold{ \sf{ \pink{ \large{W = q \triangle{V}}}}}}} \: \star$

⏭ Terms indication:

✏ W denotes work done

✏ q denotes charge

✏ ΔV denotes potential difference

⏭ Calculation:

$\implies \sf \: \red{ \triangle{V} = \dfrac{W}{q}} \\ \\ \implies \sf \: \triangle{V} = \dfrac{50}{3} \\ \\ \implies \: \underline{ \boxed{ \bold{ \sf{ \orange{ \large{ \triangle{V} = 16.67 \: Volt}}}}}} \: \gray{ \bigstar}$

⏭ Additional information:

• Electric potential is a scalar quantity while potential gradient is a vector quantity.
• The electric potential due to a charge q at its own location is not defined-it is infinite.

Answer 2

$\mathtt{ \huge{ \fbox{Solution :)}}}$

Given ,

• Work done (w) = 50 joule
• Charge (q) = 3 C

We know that , the work done to move a unit charge from one point to another point is called potential difference

$\large{\mathtt{ \fbox{Potential \: difference \: (v) = \frac{w}{q} }}}$

Thus ,

V = 50/3

V = 16.6 volt

Hence , the potential difference is 16.5 volt

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