50 kg of n2 and 10 kg of h2 are mixed to produce nh3 calculate the moles of nh3 formed identify the limiting reagent in the production of nh3 in the situation
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N2 + 3H2 ---->2NH3
here.
28kg N reacts with 6kg of H
so,
50 kg of M react with 6/28×50kg H = 10.7kg but we have only 10 so H2 is limiting reagent..
6kg H2 gives 34kg NH3
10kg H2 will give 34/6×10=56.67kgNH3
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