Question

50 kg of N2 and 10 kg of H2 are mixed to produceNH3. Calculate the moles of NH3 formed. Identify the limiting reagent in the production of NH3 in the situation

Answer 1

I don't know sorry but let this question pass to the expert

Answer 2

N2 + 3H2 ---->2NH3

here.

28kg N reacts with 6kg of H

so,

50 kg of M react with 6/28×50kg H = 10.7kg but we have only 10 so H2 is limiting reagent..

6kg H2 gives 34kg NH3

10kg H2 will give 34/6×10=56.67kgNH3

It’s basically a formula