Question

50 liter of water containing Ca(HCO3)2 when converted into soft water required 22.2g of Ca(OH)2 . Calcultated the amount of Ca(HCO3)2 per liter of hand water.​

Answer 1

The amount of $Ca(HCO_3)_2$ present in per litre of hard water is 0.972

Explanation:

The reaction is

$Ca(HCO_3)_2+Ca(OH)_2\rightarrow2CaCO_3+2H_2O$

Molecular weight of $Ca(HCO_3)_2$ is 162

Molecular weight of $Ca(OH)_2$ is 74

Thus,

74 gram (1 mole) of $Ca(OH)_2$ reacts with 162 gram of $Ca(HCO_3)_2$

Thus, 1 gram of $Ca(OH)_2$ reacts with = $\frac{162}{74}$ gram of $Ca(HCO_3)_2$

22.2 gram of of $Ca(OH)_2$ reacts with = $\frac{162}{74}\times 22.2=48.6$ gram of $Ca(HCO_3)_2$

Thus,'

50 litres of water contains 48.6 gram of $Ca(HCO_3)_2$

1 litre of water will contain $=\frac{48.6}{50}=0.972$ gram of $Ca(HCO_3)_2$

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