50 litre of dry N2 is passed through 36g of H2O at 27°C. After passage of gas, there is a loss of 1.20g in water. Calculate vapour pressure of water.
Answers
Answered by
2
Answer:
The water vapours occupies the volume of N2 gas i.e. 50 litre
∴ For H2O vapour V = 50 litre, w = 1.20g, T = 300K, m = 18
PV = w / m RT or P × 50 = 1.2 / 18 × 0.0821 × 300
∴ P = 0.03284 atm = 24.95 mm
Hope it helps you.....
Answered by
2
Answer:
24.95 atm is the required answer
Explanation:
which is provided by the above user
Similar questions