Question

50 m
The diagram given alongside shows two paths drawn inside a
rectangular field 50 meters long and 35 metres wide. The width of
cach path is 5 meters. Find the area of the shaded portion.
Calculate the area of the figure given alongside. Angles A, B, C, D, E and Fare
right angles as indicate. All measurements are in centimetres,
Find the area of the shaded region in each of the following figures 1
15 m
12 m​

Answer 1

Answer:

Length of rectangle ABCD =50\ m=50 m

Breadth of rectangle ABCD =5\ m=5 m

Area of rectangle ABCD =L\times B=L×B

=50\times 5=50×5

=250\ m^2=250 m

2

Length of rectangle EFGH =35\ m=35 m

Breadth of rectangle EFGH =5\ m=5 m

Area of rectangle EFGH =35\times5=35×5

=175\ m^2=175 m

2

Length of rectangle ILKL =5\ m=5 m

Breadth of rectangle IJKL =5\ m=5 m

Area of rectangle IJKL =35\times5=35×5

=175\ m^2=175 m

2

Now,

Area of shaded portion == (Area of ABCD ++ Area of EFGH) -− Area of IJKL

=(250+175)-25=(250+175)−25

=425-25=425−25

=400\ m^2=400 m

2

Hence area of shaded portion is 400\ m^2400 m

2

solution

Answer 2

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