Physics, asked by ayushbhandari1008, 1 month ago

50 मीटर/सेकेंड के प्रारंम्भिक वेग से फेंके गये पत्थर द्वारा ली गयी अधिकतम ऊँचाई क्या होगी?
(a)50 मीटर
(b) 125 मीटर
(c)46 मीटर
(d)48 मीटर

Answers

Answered by nileshgupta121

6

Answer:

v^2=u^2-2gh

0=50^2-2×10×h

0=2500-20h

h=-2500/-20=125m

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