Question

50 ml 10% by volume cacl2 then what molarity of cl ions are there in the solution????​ ​

Answer 1

Answer:

0.892N

Explanation:

volume%=volume of solute/v of solution × 100

10=50/volume of solution×100

v of solution=500ml=0.5L

let the process be done at STP

so

1mol of substance at STP has 22.4L volume

1mol=====>22.4

Xmol====>0.5L

X=0.5×1/22.4=0.0223 mol

molarity=moles/litrs of solution=

=0.0223/0.5=0.0446M

CaCl2 ====>Ca+² +2Cl‐¹

0.0223CaCl2/0.5L×2cl-/1CaCl2=2×0.223/0.5

=0.892M