50 ml 10% by volume cacl2 then what molarity of cl ions are there in the solution????
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Answer:
0.892N
Explanation:
volume%=volume of solute/v of solution × 100
10=50/volume of solution×100
v of solution=500ml=0.5L
let the process be done at STP
so
1mol of substance at STP has 22.4L volume
1mol=====>22.4
Xmol====>0.5L
X=0.5×1/22.4=0.0223 mol
molarity=moles/litrs of solution=
=0.0223/0.5=0.0446M
CaCl2 ====>Ca+² +2Cl‐¹
0.0223CaCl2/0.5L×2cl-/1CaCl2=2×0.223/0.5
=0.892M
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