50 ml hydrochloric acid is diluted to 250 mL, 10mL of this diluted acid neutralize 0.4 g sodium
hydroxide Calculate the strength of initial hydrochloric acid.
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Answers
Answer:
Even without doing any calculations, you can look at the values given to you and try to estimate the concentration of the hydrochloric acid solution relative to that of the sodium hydroxide.
You know that
50 mL
of this hydrochloric acid solution must contain the same number of moles of solute as
10 mL
of sodium hydroxide solution.
Since you have the same number of moles in a smaller volume, it follows that the hydrochloric acid solution will be more concentrated than the sodium hydroxide solution.
∣
∣
∣
∣
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
a
a
[
HCl
]
>
0.40 M
a
a
∣
∣
−−−−−−−−−−−−−−−−−−
So, use the molarity and volume of the sodium hydroxide solution to determine how many moles of solute it contains
...............So, use the molarity and volume of the sodium hydroxide solution to determine how many moles of solute it contains
∣As predicted, the hydrochloric acid solution was more concentrated than the sodium hydroxide solution.
[
HCl
]
>
[
NaOH
]
a
√