50 ml of 0.2 M HCL is mixed with 50 ml of 0.1M NaoH solution. The resulting solution is.
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Answer:
HCl+NaOH----------->NaCl+H2O
Concentration of HCl=0.1M
Concentration of NaOH=0.2M
So 50 ml.of 0.1M HCl will react with 25 ml.of 0.2M NaOH.
The resulting solution will contain 25 ml.of 0.2 M NaOH Equivalent in the total 100 ml.of resulting mixture.
25 ml.of 0.2 M solution contains
=25 x 0.2= 5 m.moles
1000 ml.of this solution will contain
=5 x 1000/100=5 x10
=50 m.moles=0.05M
So pOH of the solution is pOH= - log(0.05)=1.3019.
So pH=14–1.3010=12.6990
Explanation:
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