50 ml of 1 M HBr at 22.5 C is mixed with 50 mL of 1 M NaOH at 22.5C in a calorimeter. The temperature increases to 26 C. How much heat was released? The density of water is 1g/mL. The specific heat of water is 4.18J/g
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Answer:ΔH=-1463 J or 1.46 kJ
Explanation:
50 mL+50 mL= 100 ml
mass=100 mL x(1 g/1mL)= 100 g
Cwater= 4.18 J/g °C
ΔT= 26 °C - 22.5 °C=3.5 °C
ΔH=- m x C x ΔT
ΔH=-(100 g)(4.18J/g°C) (3.5°C)
ΔH=-1463 J or 1.46 kJ
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