Question

50 ml of 1 m oxalic acid is shaken with 0.5 gm of wood charcoal. The final concentration of the solution after adsorption is 0.5 m. Amount of oxalic acid absorbed per gm of charcoal is

Answer 1

Total moles of oxalic acid = 50 mmol
Final concentration = 0.5 M
Final no. of moles = 0.5/50 ml = 10 mmol
amount of oxalic acid adsorbed per gram = 40 mmol/0.5 = 80 mmol/g = 80 X 126 / 1000 = 10.08 gram of oxalic acid / gram of charcoal