Question

50 mL of 1 M oxalic acid (molar mass = 126) is shaken with 0.5 g of wood charcoal. The final concentration
of the solution after adsorption is 0.5 M. Calculate the amount of oxalic acid adsorbed per gram of charcoal
(1) 6.1
(2) 6.2
(3) 6.4
(4) 6.3​

Answer 1

Answer:

6.3

Explanation:

W=[126×1×50]/1000⇒6.3  

(Molecular weight of oxalic acid ⇒163)

0.5g→6.32

1g→6.32×0.5×1=6.3g.

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