Question

. 50 ml of a gas A diffuse through a membrane in
the same time as for the diffusion of 40 ml of a gas
B under identical pressure temperature conditions.
If the Molecular weight of A= 64, that of B would
be:
(1) 100
(3) 200
(2) 250
(4) 80​

Answer 1

Answer:

100

Explanation:

ra/rb =root under ma/mb

=va/t/vb/t=root under mb/ma

=50/t/40/t=root mb/8

root mb=8into 5/4

mb =100

Answer 2

If the Molecular weight of A= 64, that of B would  be 100

Explanation:

From Graham's law of effusion rates, the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

$\frac{rate_1}{rate_2}=\sqrt{\frac{M_2}{M_1}}$

$rate=\frac{volume}{time}$

Rate is volume effused per unit time. Since, the volumes are same, the formula could be written as:

$\frac{v_A}{v_B}=\sqrt{\frac{M_B}{M_A}}$

Putting the values in the formula:

$\frac{50ml}{40ml}=\sqrt{\frac{M_B}{64}}$

Squaring both sides:

$M_B=100$

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