Question

`50 ml of a mixture of C2H2(g) & CH4(g) was mixed with excess of O2(g) in a eudiometer tube. After explosion and cooling the mixture was treated with KOH solution when a reduction of 825 ml volume was observed. What was the mole % of CH4 in originalmixture?`​

Answer 1

Answer:

I have one example related to this questionThe contraction on cooling is due to the condensation of water vapour. Thus 17 ml of water are formed in the reaction.

The contraction in the volume of 14 ml is due to the dissolution of carbon dioxide gas. Hence, 14 g of carbon dioxide is present in the mixture after the explosion.

4.5ml

CH

4

→

4.5ml

CO

2

+

9ml

2H

2

O

4ml

C

2

H

4

→

8

2CO

2

+

8ml

2H

2

O

Hence, the composition of the mixture is 4.5 ml methane and 1.5 ml of carbon dioxide.