50 mL of standard hard water (0.2 mg/mL CaCO3) consumed 11.2mL EDT
solution for complete titration in the presence of Erichrome black T indicator.
a. 50 mL tap water requires 16.8 mL of the same EDTA for complete titration
b. 250 mL of the same tap water boiled for 1 h filtered and diluted with
distilled water to original water. 50 mL of the sample needed 9.8 mL
EDTA.
c. 40 mL of calcium precipitating buffer was stirred into 200 mL tap water
and the precipitate filtered through dry apparatus. 60 mL of the filtrate
requires 8.4 mL EDTA.
Determine the strength of EDTA and various types of hardness
Answers
Explanation:
Solution
Given :-
\sf \implies \: Equation \: 3x + 4y - 9 = 0⟹Equation3x+4y−9=0
\sf \implies Point \: (1,3) \: and \: (2,7)⟹Point(1,3)and(2,7)
Let
\sf \implies \: Ratio \: = P \ratio \: 1⟹Ratio=P:1
Using section formula
\implies \sf \: p \bigg( \dfrac{x_2m + nx_1}{m + n} , \: \dfrac{y_2m + y_1n}{m + n} \bigg)⟹p(
m+n
x
2
m+nx
1
,
m+n
y
2
m+y
1
n
)
Where
\begin{gathered} \sf \implies \: x_1 = 1, y_1 = 3 \\ \sf \implies \: x_2 = 2,y_2 = 7\end{gathered}
⟹x
1
=1,y
1
=3
⟹x
2
=2,y
2
=7
\sf \implies \: m = p \: \: and \: n = 1⟹m=pandn=1
Now put the value on formula
\sf \implies\: p \bigg( \dfrac{2 \times p + 1 \times1}{p + 1} , \: \dfrac{7 \times p + 3 \times 1}{p + 1} \bigg)⟹p(
p+1
2×p+1×1
,
p+1
7×p+3×1
)
\sf \implies\: p \bigg( \dfrac{2p + 1 }{p + 1} , \: \dfrac{7 p + 3 }{p + 1} \bigg)⟹p(
p+1
2p+1
,
p+1
7p+3
)
Now put the value of x and y on Given equation
\sf \implies \: 3x + 4y - 9 = 0⟹3x+4y−9=0
\sf \implies3 \bigg( \dfrac{2p + 1}{p + 1} \bigg) + 4 \bigg( \dfrac{7p + 3}{p + 1} \bigg) - 9 = 0⟹3(
p+1
2p+1
)+4(
p+1
7p+3
)−9=0
\sf\implies \: \dfrac{6p + 3}{p + 1} + \dfrac{28p + 12}{p + 1} - 9 = 0⟹
p+1
6p+3
+
p+1
28p+12
−9=0
Takin Lcm
\sf \implies \: \dfrac{6p + 3 + 28p + 12 - 9p - 9}{p + 1} = 0⟹
p+1
6p+3+28p+12−9p−9
=0
\sf \implies\: 6p + 3 + 28p + 12 - 9p - 9 = 0⟹6p+3+28p+12−9p−9=0
\sf \implies \: 34p + 15 - 9p - 9 = 0⟹34p+15−9p−9=0
\sf \implies 25p + 6 = 0⟹25p+6=0
\sf \implies \: p = \dfrac{ - 6}{25}⟹p=
25
−6
Answer
The ratio is -6/25 or -6:25