50% of reaction is completed in 16min, under similar conditions 75% of the reaction is completed in 48min. then the order of the reaction is?
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Given info : 50% of reaction is completed in 16 min, under similar conditions 75 % of the reaction is completed in 48 min.
To find : Then the order of the reaction is..
solution : using zero order reaction formula,
50 % of reaction is completed in 16 min.
[A] = [A]₀ - kt
here [A] = 50 % of [A]₀ and t = 16 min
so, [A]₀ = 32k ...(1)
when 75 % of reaction is completed in 48 min.
[A] = [A]₀ - 75 % of [A]₀ = 0.25 [A]₀ and t = 48 min.
so, 0.25[A]₀ = [A]₀ - k × 48
⇒[A]₀ = 32k ...(2).
from equations (1) and (2) we get,
the above reaction is zero order reaction.
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