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Answer 1

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No. of  moles of complex = M (moles/litre) ×V (litre) =0.01 × (100/1000) =0.001

[Cr(H2O)4Cl2]Cl has one ionizable Cl−

10−3 moles of the complex precipitates the same amount of AgCl

That is it would precipitate 0.001 moles of AgCl  

No this is not based on concept of common ion effect  it is simple displacement reaction

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Answer 2

heya!!
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→ Number of moles = Molarity × Volume

Here,

[Cr(H2O)4Cl2]Cl + AgNO3 ------> [Cr (H2O)4Cl2]NO3 + AgCl (ppt)


Number of moles =

= 0 .01 × 100/ 1000 = 10^-3

so, moles of AgCl = 0.001

hope it helps Bro!!

# Jaihind