Question

50. Phosphorylation of glucose is non-spontaneous at
300K. AG° is found to be 14 kJ mol-1. The
thermodynamic equilibrium constant will be
(1) 3.65 x 10-2
(2) 3.65 x 10-3
(3) 3.65 x 10-4
(4) 3.65 x 10-5
​

Answer 1

Answer:

(2) 3.65 x 10-3 is the answer

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Answer 2

Answer:

Question...

Phosphorylation of glucose is non-spontaneous at

Phosphorylation of glucose is non-spontaneous at300K. AG° is found to be 14 kJ mol-1. The

Phosphorylation of glucose is non-spontaneous at300K. AG° is found to be 14 kJ mol-1. Thethermodynamic equilibrium constant will be

Answer ⤵️

3.65 x 10-3....

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