Question

50 point







5 yrs later fathers age will be 3 time the age of son. 5 years ago father was 7 time as old as his son. find present age.






Pls solve this mates!






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Answer 1

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Let the present age of father be x years and the age of son be y years.

Five years later,

Father's age= (x+5) years

Son's age= (y+5) years

Now, According to the question

x+5= 3(y+5)

⟹x-3y-10= 0 -(1)

Five years ago, father's age= (x-5)years

Son's age= (y-5)years

Now,

(x-5)= 7(y-5)

⟹x-7y+30= 0 -(2)

Subtracting equation -(2) from -(1)

4y-40= 0

⟹y= 10

Putting y= 10 in equation -(1), we get:

4y-40= 0

⟹y= 10

Putting y= 10 in equation-(1), we get:

x-30-10= 0

⟹x= 40

Hence, present age of father is 40 years and present age of son is 10 years

Answer 2

hey friend your answer

Let the age of son be x yrs and age of his father be your yrs.

from 1st condition

(y+5) =3(x+5)

y+5=3x+15

y=3x+15-5

y=3x+10---(1)

from 2nd condition

(y-5) =7(x-5)

y-5=7x-35

7x-y=35-5

7x-y=30---(2)

put y= 3x+10 in equation (2)

7x-(3x+10) =30

7x-3x-10=30

4x=30+10

4x=40

x=40/4

x=10

put x= 10 in equation (1)

y= 3x+10=3×10+10=30+10=40

Therefore, the age of son is 10 yrs and his father's age is 40 yrs.

hope it helps you!