Question

50 points


A pole 5m high is fixed at the top of the tower. the angle of elevation of top of the pole observed from point A on the ground is 60o and the angle of depression of the point A from the top of the tower is 45o. find the height of the tower.

Answer 1

Step-by-step explanation:

Let the height of the tower be h

so \angle{BAD}=90-45=45∠BAD=90−45=45 °

the distance of the point A from the foot of tower be b

so so tan 45 = \frac{h}{b}

b

h

⇒ b = x {tan 45° = 1}

for ΔABC \angle{BAC}=60∠BAC=60 °

so tan 60° = \frac{x+5}{x}

x

x+5

⇒ √3x = x + 5

⇒ 0.732x = 5

⇒ x ≈ 6.83 m