Math, asked by arvishaali2004, 1 year ago

50 points

A takes 3 hrs more than B to walk a distance of 30 km. but if A doubles his speed he is ahead of B by 1.5 hrs . Find the speed of A and B​​

Answers

Answered by Anonymous
21

SOLUTION ☺️

=) Speed of A= x

=) Speed of B= y

Distance= 30km

1st case

 =  >  \frac{30}{x}  =  \frac{30}{y}  + 3 \\  =  >  \frac{30}{x}  - 3 =  \frac{30}{y} ............(1)

2nd Case

 =  >  \frac{30}{x}  =  \frac{30}{y } -  \frac{3}{2}   \\  =  >  \frac{30}{x}  +  \frac{3}{2}  =  \frac{30}{y} ..........(2) \\   =  > from \: (1) \: and \: (2) \\  =  >  \frac{30}{x}  - 3 =  \frac{30}{x}  +  \frac{3}{2} \:  \:  \: (axiom \: 1)  \\  =  >  \frac{30}{x}  -  \frac{30}{2x}  =  \frac{3}{2}   + 3 \\  =  >  \frac{60x - 30x}{2 {x}^{2} }  =  \frac{3 + 6}{2}  \\  =  >  \frac{30x}{ {x}^{2} }  = 9 \\  =  > 30x = 9 {x}^{2}  \\  =  > 9x = 30 \\  =  > x =  \frac{30}{9}  =  \frac{10}{3} km \: per \: hour

Speed of A= 10/3 km/hrs

Substitute in Equation (1)

 =  >  \frac{ \frac{30}{10} }{3}  - 3 =  \frac{30}{y}  \\  =  > 9 - 3 =  \frac{30}{y}  \\  =  > 6 =  \frac{30}{y}  \\  =  > 6y = 30 \\  =  > y =  \frac{30}{6} \\  =  > y = 5 \: km \: per \: hours

Speed of B= 5 km/hrs

HOPE it helps ✔️☺️


Preeti9432: Nice explanation..
Answered by Preeti9432
7

Answer:

Let speed of A = x km/h

Speed of B = y km/h

Distance = 30 km

Time taken by A to walk 30 km =

distance /speed = 30/x hr

Time taken by B to walk 30 km = 30/yhr

According to the given condition,

30/x + 30/y = 3

Dividing both side by 3 we get,

10/x + 10/y = 1 ----------(1)

If A double his speed he is ahead of B by 1.5 hr means 3/2 hr.

When A double his speed = 2x km/hr

Time taken by A to walk 30 km = 30/2x hr

According to the given condition,

30/y = 30/2x + 3/2

Dividing both side by 3/2 we get,

20/y = 10/x + 1 ----------(2)

Put 1/x = a & 1/y = b

From eqn.(1) 10a = 10b +1

10a - 10b = 1 ------------(3)

From eqn. (2) 20b= 10a + 1

10a - 20b = -1 ------------(4)

Subtracting eqn. (4) from eqn. (3) we get,

10a - 10b -(10a - 20b) = 1-(-1)

10a - 10b - 10a + 20b = 2

10b = 2

b = 2/10

b = 1/5

1/y = 1/5

y = 5

Put the value of b in eqn. (3) we get,

10a -10 ×1/5 = 1

10a -2 = 1

10a = 1 + 2

10a = 3

a = 3/10

1/x = 3/10

x = 10/3

Speed of A = 10/3 km/hr

Speed of B = 5 km/hr

Hope it helps! ! !


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