50 points
A takes 3 hrs more than B to walk a distance of 30 km. but if A doubles his speed he is ahead of B by 1.5 hrs . Find the speed of A and B
Answers
SOLUTION ☺️
=) Speed of A= x
=) Speed of B= y
Distance= 30km
1st case
2nd Case
Speed of A= 10/3 km/hrs
Substitute in Equation (1)
Speed of B= 5 km/hrs
HOPE it helps ✔️☺️
Answer:
Let speed of A = x km/h
Speed of B = y km/h
Distance = 30 km
Time taken by A to walk 30 km =
distance /speed = 30/x hr
Time taken by B to walk 30 km = 30/yhr
According to the given condition,
30/x + 30/y = 3
Dividing both side by 3 we get,
10/x + 10/y = 1 ----------(1)
If A double his speed he is ahead of B by 1.5 hr means 3/2 hr.
When A double his speed = 2x km/hr
Time taken by A to walk 30 km = 30/2x hr
According to the given condition,
30/y = 30/2x + 3/2
Dividing both side by 3/2 we get,
20/y = 10/x + 1 ----------(2)
Put 1/x = a & 1/y = b
From eqn.(1) 10a = 10b +1
10a - 10b = 1 ------------(3)
From eqn. (2) 20b= 10a + 1
10a - 20b = -1 ------------(4)
Subtracting eqn. (4) from eqn. (3) we get,
10a - 10b -(10a - 20b) = 1-(-1)
10a - 10b - 10a + 20b = 2
10b = 2
b = 2/10
b = 1/5
1/y = 1/5
y = 5
Put the value of b in eqn. (3) we get,
10a -10 ×1/5 = 1
10a -2 = 1
10a = 1 + 2
10a = 3
a = 3/10
1/x = 3/10
x = 10/3
Speed of A = 10/3 km/hr
Speed of B = 5 km/hr
Hope it helps! ! !