Question

50 points...
Appropriate answer will be marked as brainliest....
Hybridisation of each of the following:-
1.)CH4,
2.)SF4,
3.)ICl2-

Answer 1

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`$\textbf{Hyberdisation}$`

The process of mixing of orbitals with the different energy levels and shapes of the orbitals is called hyberdisation.

`$\textbf{1. Hyberdisation of CH4}$`

Valence electrons of C = 4

Valence electrons of H = 1

Given atoms of H = 4

Using formula :- ½ (V + M - C + A)
= ½ (4 + 4)
= 8

Hyberdisation of CH4 = Sp³

→ {structures are in attachment.}

`$\textbf{2. Hyberdisation of SF4}$`

Valence electrons of S = 6

Atoms of of F = 4

Using formula we get :- ½ (6 + 4)
= 5

Hyberdisation of SF4 = Sp³d

`$\textbf{3. Hyberdisation of ICl²-}$`

Valence electrons of I = 7

Atoms of Cl = 2

Using formula we get = ½ (7 + 2 + 1)
= 5

Hyberdisation of ICl-² = Sp³

Answer 2

see the following hybridization of ch4
c is the central atom which has four different valency electrons
four different atoms are bonded by four single bonds.

hybridization of sf4

four different atoms of f and has six different Valence Electrons


hybridization of ICI2

CI ATOMS ARE 2

number of valencies of electrons is 7 of I