Question

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Answer 1

Check the attachment!!

Answer 2

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Reaction

2AL+ NaoH+ 2h20 --------> 2NaALo2 + 3H2

As,

P1=1 bar

P2=1 bar

T1= 273 K

T2=273+20=293 K

V1= 0.15 × 3 ×22.4 =187 ml

54

V2 be x ml

P1 V1 =P2 V2

T1 T2

P1 V1 T2 =V2

T1 P2

1×187×293 = V2

0.987×273

V2 = 210 ml

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