Question

50 points fastly please​

Answer 1

☯ AnSwEr :

$\begin{lgathered}\boxed{a} + \boxed{b} = 8 \\ + \: \: \: \: \: \: \: + \\ \boxed{c} - \boxed{d} = 13 \\ | | \: \: \: \: \: \: \: \: \: \: | | \\ 13\: \: \: \: \: \: \: \: 8\end{lgathered}$

Now, we get

a + b = 8 ......(1)

a + c = 13 .......(2)

b + d = 8 ......(3)

c - d = 6.......(4)

$\rule{200}{2}$

↪From equation 1.

a = 8 - b

★ Put value of a in equation 2.

→ 8 - b + c = 13

→ -b + c = 13 - 8

→ -b + c = 5 .......(5).

$\rule{200}{2}$

↪From equation 3.

d = 8 - b

★ Put value of b in equation 4.

→ c - (8 - b) = 6

→ c -8 + b = 6

→ c + b = 6 + 8

→ c + b = 14 .......(6)

$\rule{200}{2}$

↪From equation 5.

c = 5 + b

★ Put value of c in equation 6.

→ 5 + b + b = 14

→ 2b + 5 = 14

→ 2b = 14 - 5

→ 2b = 9

→ b = 9/2

→ b = 4.5

$\Large{\implies{\boxed{\boxed{\sf{b = 4.5}}}}}$

$\rule{200}{2}$

★ Put value of b in equation 1.

→ a + 4.5 = 8

→ a = 8 - 4.5

→ a = 3.5

$\Large{\implies{\boxed{\boxed{\sf{a = 3.5}}}}}$

$\rule{200}{2}$

★ Put value of a in equation 2.

→ 3.5 + c = 13

→ c = 13 - 3.5

→ c = 9.5

$\Large{\implies{\boxed{\boxed{\sf{c = 9.5}}}}}$

$\rule{200}{2}$

★ Put value of c in equation 4.

→ 9.5 - d = 6

→ -d = 6 - 9.5

→ -d = -3.5

→ d = 3.5

$\Large{\implies{\boxed{\boxed{\sf{d= 3.5}}}}}$

$\rule{200}{2}$

Now, we get

$\begin{lgathered}\boxed{3.5} + \boxed{4.5} = 8 \\ + \: \: \: \: \: \: \: \: \: \: \: + \\ \boxed{9.5} - \boxed{3.5} = 13 \\ | | \: \: \: \: \: \: \: \: \: \: \: \: \: \: | | \\ 13\: \: \: \: \: \: \: \: \: \: \: \: 8\end{lgathered}$

Answer 2

Answer:

$\:$

Step-by-step explanation:

supposed:-

1)a+b=8............. Equation 1.

2)c-d=6............. Equation2.

3)a+c=13............. Equation 3.

4)b+d=8............. Equation 4.

From equation b=8-a

From equation b=8-aSubstitute ‘b’ value in Equation 4

Then equ.4) becomes

(8-a)+d=8

d-a=8–8=0

d=a

Replace 'd' with 'a' in equ.2)

2) c-a=6

3) a+c=13

(Summing up equa.2 &equa.3)

will give value of ‘c,a&d’

2c=19, c=9.5

Substitute c value in Equation 2

a= 9.5–6

a=d=3.5

Substituting ‘a=d=3.5’ value in Equ.1 or equ.4

gives value of 'b'

b=4.5

a=3.5, b=4.5, c=9.5, d=3.5