Question

50 points for one question (7)

Answer 1

Hey mate!!

The answer is here...
________________________________

Given:

Area of trapezium = 180 cm²
Height = 9 cm

let 1 parallel side be = x cm 

other parallel side = (6 + x) cm

We know that

Area of trapezium = $\bold{ \frac{1}{2} \times sum \: of \: parallel \: sides \: \times height}$

=> 1/2 × {x + 6 + x} × 9 = 180

=> 1/2 × ( 2x + 6 ) × 9 = 180

=> 9 ( 2x + 6 ) = 180 × 2

=> 18x + 54 = 360

=> 18x = 360 - 54

=> 18x = 306

=> x = 306/18

=> x = 17

First || side = 17 cm.

Second || side = ( 17 + 6 ) = 23 cm.


$\bold{\large{\underline{Verification :-}}}$

$\frac{1}{2} \times (23 +1 7) \times 9 \\ \\ \frac{1}{ \cancel2} \times \cancel{40 } \: \: {}^{20} \times 9 \\ \\ 20 \times 9 \\ \\ 180 \: \: cm {}^{2}$

Hence, the answer is right.

First || side = 17 cm.

Second || side = ( 17 + 6 ) = 23 cm.



Thanks for the question!

☺☺☺

Answer 2

hi

this is an easy question

ATQ,

area of trapezium is 180cm²

height = 9cm

1/2(A+B)H = 180

one of the pareller sides is longer than other one by 6m

so

let one parellel side be a . then other one is a+6

=> 1/2(a +a+6)9 = 180

=>1/2 +18a+54 = 180

=> 18a +54 = 360

18a =360-54

18a = 306

a =17

other side = a+6

=> 17 +6

=> 23 cm

hope it helps u

:)