Question

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Answer 1

Answer:

a.

probability of opening lock in one attempt=1/10

b.

i)Number of possible combinations

0-0,1,2,3-----9 =10

1-0,1,2--------9 =10

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9-0,1,2,------9 =10

Number of possible combinations=10×10=100

ii)probability of opening lock in one attempt=1/100

c.

i)Number of possible combinations

0-1-0,1,2------9

-2-0,1,2-----9

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-9-0,1,2,3----9 = 100

Similarly for 10 numbers= 100×10 =1000

Number of possible combinations=1000

ii))probability of opening lock in one attempt=1/1000

Answer 2

Answer:

a. 1/9

b. i) No. of possible combinations = 100

ii) 1/100

c. i) no. of possible combinations =1000

ii) 1 / 1000

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