Question

(50 points)
....................

In a sample of naturally occuring iron oxide, every 30 out of 200 Fe2+ ions are missing.The loss of

positive charge is made up by adding required number of Fe3+ ions so as to restore electrical neutrality.The

net formula for this sample is:​

Answer 1

Let's assume that there are x molecule fraction of Fe

+2

& 0.93−x molecular fraction of Fe

+3

.

Now, using charge conservation formula for Fe

0.96

O

1.00

, we get

⇒x(+2)+(0.99−x)(+3)−2=0

⇒2x−3x+2.79−2=0

⇒x=0.79

Fraction of Fe

+2

=0.79 & frcation of Fe

+3

=0.14

Percentage of Fe

+2

=

0.93

0.79

×100=84.9%

Percentage of Fe

+3

=

0.93

0.14

×100=15.05%

Hope it will help you......

Answer 2

Let's assume that there are x molecule fraction of Fe

+2

& 0.93−x molecular fraction of Fe

+3

.

Now, using charge conservation formula for Fe

0.96

O

1.00

, we get

⇒x(+2)+(0.99−x)(+3)−2=0

⇒2x−3x+2.79−2=0

⇒x=0.79

Fraction of Fe

+2

=0.79 & frcation of Fe

+3

=0.14

Percentage of Fe

+2

=

0.93

0.79

×100=84.9%

Percentage of Fe

+3

=

0.93

0.14

×100=15.05%

Hope it will help you

Please mark me as brainlist...