Math, asked by DevRanKumar, 1 month ago

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Answer with Indonesian Language!
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Tentukanlah akar-akar nilai x dari persamaan kuadrat x² - 6x + 8 = 0
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Answers

Answered by tejeswarteju
1

Answer:

x {}^{2}  - 4x - 2x  + 8 = 0

x(x - 4) - 2(x - 4) = 0

(x - 2)(x - 4) = 0

x = 2 \:  \: and \:  \:  \: x = 4

Answered by Thesager
0

Answer:

x {}^{2} - 4x - 2x + 8 = 0x

2

−4x−2x+8=0

x(x - 4) - 2(x - 4) = 0x(x−4)−2(x−4)=0

(x - 2)(x - 4) = 0(x−2)(x−4)=0

x = 2 \: \: and \: \: \: x = 4x=2andx=4

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