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Tentukanlah akar-akar nilai x dari persamaan kuadrat x² - 6x + 8 = 0
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x {}^{2} - 4x - 2x + 8 = 0x
2
−4x−2x+8=0
x(x - 4) - 2(x - 4) = 0x(x−4)−2(x−4)=0
(x - 2)(x - 4) = 0(x−2)(x−4)=0
x = 2 \: \: and \: \: \: x = 4x=2andx=4
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