Question

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Question:Determine k so that k+2, 4k - 6 and 3k - 2 are the three consecutive terms of an AP.
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Answer 1

Answer:

k=3

Step-by-step explanation:

steps are in the given photo... hope everything is clear.

Answer 2

Answer:

Given:( 3k-2), (4k-6) and (k+2) are three consecutive terms of an AP.

To find The value of k

Let a= 3k-2

a2= 4k -6

a+d = 4k -6

3k-2 +d = 4k -6

d = k-4

a3 = k+2

a+ 2d = k+2

3k-2 +2k -8= k+2

5k -10 = k+2

4k = 14

k = 7/2