Question

50 Points!! Only Answer Of You Know. Otherwise I Will Report And Your Answer Will Be Deleted And You Wont Get Any Point.ok

50 Points!! Only Answer Of You Know. Otherwise I Will Report And Your Answer Will Be Deleted And You Wont Get Any Point.ANSWER ONLY IF YOU KNOW.... DON'T ANSWER JUST FOR POINTS OTHERWISE I WILL REPORT YOUR ANSWER​

I Still Didnt Got Correct answer!

50 Points!! Only Answer Of You Know. Otherwise I Will Report And Your Answer Will Be Deleted And You Wont Get Any Point.Instead A Warn!

Question:Determine k so that k+2, 4k - 6 and 3k - 2 are the three consecutive terms of an AP.
​​

Answer 1

Answer:

Given:( 3k-2), (4k-6) and (k+2) are three consecutive terms of an AP.

To find The value of k

Let a= 3k-2

a2= 4k -6

a+d = 4k -6

3k-2 +d = 4k -6

d = k-4

a3 = k+2

a+ 2d = k+2

3k-2 +2k -8= k+2

5k -10 = k+2

4k = 14

k = 7/2  

Therefore answer the value of k is 7/2.

Answer 2

$answer$

To be terms of an AP the difference between two consecutive terms must be the same

So if k+2, 4k-6 & 3k-2 are terms of an AP, then

4k-6–(k+2) = 3k-2–(4k-6)

4k-6-k-2=3k-2-4k+6

3k-8= –k+4

4k = 12

k =12/4=3

Thus the value of k is 3

HOPE IT HELPS..... :-)