Question

50 points...

Please answer as soon as possible...
Correct answer will be marked as brainliest...
Expand y= sin^-1x using maclaurin's theorem...
Please give appropriate answer...

Answer 1

series expansion can be used here as follows:
Series expansion at x = 0:
Sin^-1(x) =x + x^3/3! + 3^2.x^5/5! + 3^2.5^2.x^7/7! + 3^2.5^2.7^2.x^9/9! + 3^2.5^2.7^2.9^2.x^11/11!.......and so on.
This is the same as:
Sin^-1(x) = x + [1/2.3]x^3 + [1.3/2.4.5]x^5 + [1.3.5/2.4.6.7]x^7 + [1.3.5.7/2.4.6.8.9]x^9....etc.
The steps here are self-explanatory.

Answer 2

i hope this solves your doubt