Math, asked by rajmachawal, 1 year ago

50 points please solve ​

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Answered by Anonymous
0
first of all it is 5ab instead of ab

so here is new answer
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Answered by Anonymous
1

Hey mate....

here's the answer....

9x2-9(a+b)x+(2a2+5ab+2b2)=0

9x2 - 9(a + b)x +

(2a2 + 4ab + ab + 2b2) = 0

9x2 - 9(a + b)x +

[2a(a + 2b)

+ b(a + 2b)] = 0

9x2 - 9(a + b)x + [(a + 2b)

(2a + b)] = 0

9x2 – 3[(a + 2b) + (2a + b)]x + [(a + 2b)(2a + b)] = 0

9x2 – 3(a + 2b)x - 3(2a + b)x + [(a + 2b)(2a + b)] = 0

3x[3x  – (a + 2b)] -

(2a + b)[3x + (a – 2b)] = 0

[3x  – (a + 2b)]

[3x - (2a + b)] = 0

[3x – (a + 2b)] = 0

[3x - (2a + b)] = 0

3x  =  (a + 2b)

3x = (2a + b)

x = (a + 2b)/3 or

x = (2a + b)/3    

Hope it helps ❤️

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