Question

50 points !!!!!

Please solve Q24. Do (i)&(ii)
Full solution with easy explanation please.
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Answer 1

1. The probability of getting 2 heads = no of times 2 heads appeared \ all attempts
so , p(2 heads) = 72\200
= 36\100
= 0.36
2.The probability of getting at least 2heads = number of times we had 2 heads and 3 heads \ total attempts
=( 23 + 72 )\200
= 95\200
= 0.475
WISH IT HELPS : )

Answer 2

p(getting two heads)=no of times observation occured divided by total of observation
a. 72\200=9\25.