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What is the potential Difference across 4 ohm resistor in the given figure??​

Answer 1

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Answer 2

Question:-

What is the potential Difference across 4 ohm resistor in the given figure??

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The circuit can be reduced, step by step, to a single equivalent resistance. The 8 ohm and the 8 ohm are connected in parallel , and so they can be replaced by an equivalent resistor Rp of 4 ohms, using the below equation.

Rp= (8×8)/(8+8) =4ohms

This resistor is connected in series with the 4 ohm resistor R1. The total resistance Rt of the circuit is then

R t =R 1 +Rp =4+4=8ohms.

Since the 4 ohm and the 4 ohm are connected in series, they have the same current I1, which must be equal to the current of the battery. Using Ohms law we get,

I= RV = 8/8 =1A.

Hence, the current flowing through the resistor R1 (4 ohms) is 1A.

Now the potential difference across the resistor R1 (4 ohms) is given as follows.

V=IR=1×4=4V

Hence, the potential difference across the resistor R1 (4 ohms) = 4V.

hope it helps you..