CBSE BOARD X, asked by Anonymous, 11 months ago

50 points que plzz plzz plzz frnds tell me how in 7 ans it came 2 upon 2 while finding the maximum current through 8 ohm resistor

Attachments:

Answers

Answered by dasy31
5

Volt (V) = I×R

Power =V × I =I²R = V²/R


Where:

V is the voltage across the resistor in Volts

I is in current flowing through the resistor in Amperes

R is the resistance of the resistor in Ohm’s (Ω)



Since 8ohm is double of 4ohm , as resistance is inversely proportion to current , so it will take 1/2 of current of 4ohm.

So 1/2×2 = 1 A


Thats why maximum current flow is 1A


dasy31: Please mark it brainly.
Anonymous: i will definitely mark it
Anonymous: why 1 upon 2
Anonymous: is it applicable for all sutuations
Anonymous: plzz reply
Anonymous: plzz
Anonymous: pl tell me
Anonymous: tomorrow is my exams
dasy31: why 1 upon 2
dasy31: Answer 8ohm is double of 4ohm , since resistance is inversely proportion to current , so it is 1/2 current of 4ohm.
Answered by Anonymous
1
Heya Mate !!!

Here's Your Answer ⏬

≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈
Step by Step Explanation ;-
≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈

=> Volt (V) = I×R

=> Power =V × I =I²R = V²/R

As ;

=> V is the voltage across the resistor in Volts.

=> I is in current flowing through the resistor in Amperes.

=> R is the resistance of the resistor in Ohm’s (Ω).

=> Being 8ohm is double of 4ohm , as resistance is inversely proportion to current , so it will take 1/2 of current of 4ohm.

So 1/2×2 = 1 A

Hence , 1A is the answer.
Similar questions