Physics, asked by Dimplepathak, 11 months ago

50 points question
please solve 14 question..​

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Answered by LovelyG
1

Answer:

As it is given that, the three charges are in a line. [See the picture]

Let Q₁ be a test positive charge, since charges of Q₂ and Q₃ are opposite in sign, there exists an attractive force between them.

One point to be kept in mind here is that the net force on Q₃ must be 0 as given in the problem.

In order to keep force on Q3 be 0, the force between Q1 and Q3 must be force of repulsion as we already have attractive force between Q2 and Q3

Now to satisfy the equilibrium position, the two forces must balance each other.

KQ₁Q₃/4R2 = -KQ₂Q₃/R2….. (distance between Q1 and Q3 is 2R).

Q₁ = -4Q₂

Hence charge of Q₁ is opposite to that of Q₂ and same as that of Q₃.

_______________________

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Dimplepathak: thank you so much
LovelyG: Welcome :)
Dimplepathak: can you help me in other questions
LovelyG: Question are tough ! Still I'm trying
Dimplepathak: ok ,I'm waiting
LovelyG: Sorry! But I failed to solve :(
Dimplepathak: it's ok
Dimplepathak: don't say sorry ।।।
Dimplepathak: you helped me alot
LovelyG: :)
Answered by chica32
0

Answer :-

As it is given that, the three charges are in a line. [See the picture]

Let Q₁ be a test positive charge, since charges of Q₂ and Q₃ are opposite in sign, there exists an attractive force between them.

One point to be kept in mind here is that the net force on Q₃ must be 0 as given in the problem.

In order to keep force on Q3 be 0, the force between Q1 and Q3 must be force of repulsion as we already have attractive force between Q2 and Q3

Now to satisfy the equilibrium position, the two forces must balance each other.

KQ₁Q₃/4R2 = -KQ₂Q₃/R2….. (distance between Q1 and Q3 is 2R).

Q₁ = -4Q₂

Hence charge of Q₁ is opposite to that of Q₂ and same as that of Q₃

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