◆50 points question◆ solve on copy...
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HEY MATE HERE IS YOUR ANSWER IN ATTACHMENT
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soniamehfooz25:
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Hi ✌️✌️
SinA = 3/5 ,
Cos = Base / Hypotenuse
P = 3k
H = 5k
B2 = H2 + P2
= 25 k2 + 9 k2
= 16 k2
= 4k
Cos = 4/5
(tanA + secA)2
( sin/cos + 1/cos)2
[ 3/5 × 5/4 + 5/4]2
( 3/4 + 4/4 )2
(8/4)2 = (2)2 = 4
❤️❤️❤️
SinA = 3/5 ,
Cos = Base / Hypotenuse
P = 3k
H = 5k
B2 = H2 + P2
= 25 k2 + 9 k2
= 16 k2
= 4k
Cos = 4/5
(tanA + secA)2
( sin/cos + 1/cos)2
[ 3/5 × 5/4 + 5/4]2
( 3/4 + 4/4 )2
(8/4)2 = (2)2 = 4
❤️❤️❤️
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