Question

◆50 points question◆ solve only on copy...

Answer 1

PLEASE SEE THE PHOTO FOR ANSWER

Answer 2

$\underline{\underline{\Huge\mathfrak{Solution ;}}}$

$= > let \: ( {x}^{2} + {a}^{2} ) = u$

$= > \frac{d(u)^{ \frac{1}{2} } }{dx} = \frac{1}{2} {u}^{ \frac{ - 1}{2} } \frac{du}{dx}$

$= > \frac{1}{2} ( {x}^{2} + {a}^{2})^{ \frac{ - 1}{2} } \frac{d( {x}^{2} + {a}^{2}) }{dx}$

$= > \frac{1}{2} \times \frac{1}{ \sqrt{ {a}^{2} + {a}^{2} } } \times 2x + 2a$

$= > \frac{1}{2 \sqrt{ {x}^{2} + {a}^{2} } } \times 2x + 2a$

$= > \frac{2x + 2a}{2 \sqrt{ {x}^{2} + {a}^{2} } }$

$= > \frac{d( {x}^{2} + {a}^{2} ) }{dx} = \frac{x + a}{ \sqrt{ {x}^{2} + {a}^{2} } }$

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