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HELO GUYS
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^2 = 64, find the value of ab+bc+AC?
(a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca (formula)
(a+b+c)^2 = a^2 + b^2+ c^2 + 2(ab+bc+ca)
12^2= 64+2(ab+bc+ca) ( Substituting the given values)
144= 64+2(ab+bc+ ca)
144–64 = 2(ab+bc+ca) (solving)
80= 2(ab+bc+ ca)
80/2 = ab+bc+ca
40 = ab+ bc+ ca
Ans: 40
Synaya:
my question is diff
Answered by
2
Hola!
Here is your answer.
Answer: 2(a^3+b^3+c^3-3abc)
Answer: 2(a^3+b^3+c^3-3abc)Or
2a^3+b^3+c^3-6abc.
Detailed answer is in the attachment.
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