Math, asked by Synaya, 1 year ago

50 points
simplify step by step
2(a + b + c)(a {}^{2}  + b {}^{2}  + c {}^{2}  - ab - bc - ca)

Answers

Answered by SnehaG
4

HELO GUYS

ANSWER

^2 = 64, find the value of ab+bc+AC?

(a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca (formula)

(a+b+c)^2 = a^2 + b^2+ c^2 + 2(ab+bc+ca)

12^2= 64+2(ab+bc+ca) ( Substituting the given values)

144= 64+2(ab+bc+ ca)

144–64 = 2(ab+bc+ca) (solving)

80= 2(ab+bc+ ca)

80/2 = ab+bc+ca

40 = ab+ bc+ ca

Ans: 40


Synaya: my question is diff
soumya2301: hlo
Answered by tavilefty666
2

Hola!

Here is your answer.

Answer: 2(a^3+b^3+c^3-3abc)

Answer: 2(a^3+b^3+c^3-3abc)Or

2a^3+b^3+c^3-6abc.

Detailed answer is in the attachment.

If you've any doubt, feel free to ask in the comment section.

Thank you

Attachments:

Synaya: hii
tavilefty666: this is 100% correct
tavilefty666: plz give brainliest.
Synaya: the ans is 1/2(a+b+c)(a2+b2+c2-ab-bc-ca)
tavilefty666: how?, you've written 2 not 1/2
tavilefty666: in the question
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