Question

50 points!


(x-1)(x+2)-1=0

Solve into complete square !

Answer 1

(x-1)(x+2)-1=0

x(x+2)-1(x+2) = 0

x^2 + 2x - x - 2 = 0

x^2+ x - 2 = 0

this is your answer...

hope it helps to you ....

Answer 2

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$\bold{Method\:no.\:1}$


$(x-1)(x+2)-1=0$

$x(x+2)-1(x+2)=0$

${x^2}$ $+2x-x-2=0$

${x^2}$ $+x-2=0$


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$\bold{Method\:no.\:2}$

$\bold{Use\:the\:formula:}$

$( \frac{b}{2} )^{2}$

In order to create a new term.

$\bold{Now,}$

Solve for $x$ by using this term to complete the square.

$\bold{Exact\:Form:}$

$x = ± \frac{ \sqrt{13} }{2} - \frac{1}{2}$

$\bold{Decimal\:form:}$

$x = 1.3028$


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