Math, asked by maths345, 11 months ago

*50 Points*
(x2+2xy-3y2) - (2x2-4xy-5y2) =

Answers

Answered by raushankumar3604
5

Answer:

 ({x}^{2}  + 2xy - 3 {y}^{2} ) - (2 {x}^{2}  - 4xy - 5 {y}^{2} ) \\  {x }^{2}  + 2xy - 3 {y}^{2}  - 2 {x}^{2}  + 4xy + 5 {y}^{2}  \\  {x}^{2}  - 2 {x}^{2}  + 2xy + 4xy - 3 {y}^{2}  + 5y {}^{2}  \\  -  {x}^{2}  + 6xy + 2 {y}^{2}

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Answered by adiladil
0

Answer:

=x^2 + 2xy - 3y^2 -2x^2 -4xy -5y^2

= -x^2+2xy18y^2

= -(x^2-2xy-8y^2)

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