Math, asked by Talking322, 11 months ago

50 pts.
Points 50


sum of the digit of a two digit number is 12. New number formed by reversing the digit is greater than the original by 54. Find the original number.

Solve by both one and two variable.

and plz explain every point of your solution

Answers

Answered by suruchi9813
1

hope its helpful for you please mark be brainly

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Answered by adarsh8472
0

hey buddy your answer is here

in two variables

let both unit and tense place digit be x and y respectively.

a/q

x+y=12

x=12-y equation 1.

no formed =10y+x

no formed by reversing the digit=10x+y

a/q

10x+y-54=10y +x

by putting the value of x from eq. 1

10*12-y+y-54=10y+12-y

120-10y+y-54=9y+12

-9y+66=9y+12

-9y-9y=12-66

-18y=-54

y=-54/-18

y=3

then, x=12-uy

x=12-3=9

original no .

10y+x=10*3+9=30+9=39

in one variable

let unit digit be x

then tense place digit=12-x

no formed =10*12-x+x

=120-10x+x

=120-9x

a/q

10*x+12-x-54=120-9x

10x+12-x-54=120-9x

9x-42=120-9x

9x +9x=120+42

18x=162

x=162/18

x=9

no formed=120-9x

=120-9*9

=120-81

= 39

hope it will help you please mark me as a brain list ✌✌

if there will be an option of bracket I would explain u better

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