50 pts.
Points 50
sum of the digit of a two digit number is 12. New number formed by reversing the digit is greater than the original by 54. Find the original number.
Solve by both one and two variable.
and plz explain every point of your solution
Answers
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hey buddy your answer is here
in two variables
let both unit and tense place digit be x and y respectively.
a/q
x+y=12
x=12-y equation 1.
no formed =10y+x
no formed by reversing the digit=10x+y
a/q
10x+y-54=10y +x
by putting the value of x from eq. 1
10*12-y+y-54=10y+12-y
120-10y+y-54=9y+12
-9y+66=9y+12
-9y-9y=12-66
-18y=-54
y=-54/-18
y=3
then, x=12-uy
x=12-3=9
original no .
10y+x=10*3+9=30+9=39
in one variable
let unit digit be x
then tense place digit=12-x
no formed =10*12-x+x
=120-10x+x
=120-9x
a/q
10*x+12-x-54=120-9x
10x+12-x-54=120-9x
9x-42=120-9x
9x +9x=120+42
18x=162
x=162/18
x=9
no formed=120-9x
=120-9*9
=120-81
= 39
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if there will be an option of bracket I would explain u better