Math, asked by zoyaparveen, 10 months ago

50 students enter for a school javelin throw competition the distance thrown are recorded below ​

Attachments:

Answers

Answered by amitnrw
9

48.8 m is mean Distance , 49.4 m is median distance , 50.9  m is Mode

Step-by-step explanation:

Distance         f               cf       Mean distance       mean * f

0 - 20             6               6            10                          60

20 - 40           11               17           30                        330

40 - 60           17              34          50                        850

60 - 80           12             46           70                        840

80 - 100          4               50          90                        360

    Total         50                                                         2440

Mean = 2440/50 = 48.8

48.8 m is mean Distance

Median lies in 40-60

40 +  20 * (25 - 17)/17

= 40 + 9.4

= 49.4  m

49.4 m is median distance

Mode lies in 40-60

Mode = 40  + 20  * (17 - 11)/(17 - 11 + 17 - 12)

= 40  + 10.9

= 50.9  m is Mode

Learn more:

Find the mode, median and mean for the following data: Marks ...

https://brainly.in/question/7477608

a total of 25 patients admitted to a hospital are tested for blood sugar ...

https://brainly.in/question/7508656

Similar questions