50 students sit in a class room. Each student requires 9 m² on floor and 108 m³ in space. If the length of the room is 25 m, find its breadth and height.
Answers
EXPLANATION.
50 students sit in a classroom.
Each students required 9m² on floor and 108m³ in space.
Length of the room is 25m.
As we know that,
Total area required by students = 50 x 9 = 450m².
As we know that,
Area = Length x Breadth.
⇒ 450 = 25 x Breadth.
Breadth = 18 m.
Volume required by each students = 108m³.
Total volume of classroom = 108 x 50 = 5400m³.
As we know that,
Formula of :
Total volume = Length x Breadth x Height.
Using this formula in the equation, we get.
Put the values in the equation, we get.
⇒ 5400 = 25 x 18 x Height.
⇒ 5400 = 450 x Height.
Height = 12m.
Breadth of the classroom = 18m.
Height of the classroom = 12m.
Given :
50 students sit in a classroom.
Each student requires 9m² on the floor and 108m³ in space.
Length of the Classroom is is 25m.
To Find :
Height and Breadth.
Solution :
➻ Total Area Required by Students
⇒ 50 x 9
⇒ 450m²
➻ Calculating Breadth of Classroom :
By using, Area = Length * Breadth
⇒ 450 = 25 * Breadth
⇒ Breadth of Classroom = 18m .
➻ Total Volume of Classroom
⇒ 108 * 50
⇒ 5400m³
➻ Calculating Height of Classroom :
By using, Volume = Length * Breadth * Height
⇒ 5400 = 450 * Height
⇒ Height = 5400/450
⇒ Height of Classroom = 12m .
FINAL ANSWER :
Height of Classroom = 12m
Breadth of Classroom = 18m