Question

50) The average of a set of numbers reduces from 14 to 11 when the number 35 is remover How many numbers were in the original set? a)8 b) 11 C) 21 d)25​

Answer 1

11 = S-35/n-1 S-35=11(n-1) S-35=11n-11 S-11n=24-->Eqn 2 In Eqn 1 we have S=14 n substitute in Eqn 2 14n-11n=24 3n=24 n=8 So,Total numbers in a original set equals to 8