Question

50. The distance travelled by a body in the nth sec- ond is given by the expression (2 + 3n). Find the initial velocity and acceleration. Also, find its velocity at the end of 2 seconds.​

Answer 1

Answer:

this is a very very easy question the answer is 2.5 please follow my account like this answer I hope node is your answer is help in study

Answer 2

Answer:

As we know that the distance travelled by the body is given as 2 + 3n. Now as we know that according to the first law of motion. Speed at the end of t seconds is calculated as v = u + at, where u is the initial velocity and a is the acceleration. Hence, the velocity at the end of two seconds will be 9.5 m/sec.