Physics, asked by bhatsaleem, 1 month ago

50. The equations of motion of a projectile are given by 36t m and 2y = 96t – 9.8t2 m. The angle of projection is​

Answers

Answered by siddhayyadav
1

Answer:

Answer

Correct option is

A

sin

−1

(4/5)

Given: x−36t,2y=96t−9.8t

2

or y=48t−4.9t

2

Let the initial velocity of projectile be u and angle of projection is θ. Then,

Initial horizontal component of velocity,

u

x

=ucosθ=

dt

dx

t=0

=36 or ucosθ=36---(i)

Initial vertical component of velocity,

u

y

=usinθ=

dt

dy

t=0

=48 or usinθ=48---(ii)

Dividing (ii) by (i), we get

tanθ=

36

48

=4/3

∴sinθ=4/5

or θ=sin

−1

(4/5)

Similar questions