Question

50. The expression of solubility product of mercurous
iodide is :-
(1) (2 Hg+12 x 2 (1-12 (2) [Hg++)2 x [ 21-12
2+
(3) (Hg.* ] x [1-12
(4) [Hg2+)2 x [1-12
IE0059​

Answer 1

Answer:(3)

Explanation:mercurous iodide(HgI2)

HgI2 = Hg2+ + 2I-

Ksp = [Hg2+] [I-]^2