Question

50. The half life of a radioactive nuclide is 20 hrs. The fraction of the original activity that will remain after 40 hrs is
(A) 1/8
(B) 1/2
(C) 1/4
(D) 1/6​

Answer 1

Answer:

option c

Explanation:

1/4

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Answer 2

Answer:

1/4

Explanation:

t½=0.693/lambda

(lambda=decay constant)

N=N0e^(-lambda N0=1,N=(1/x)N=e^(lambda t)

[1/(1/x)]=e^{t½/0.693×t)

=e^{20/0.693×40}

x=3.99~4

Fraction=1/x=1/4